document.write( "Question 92952: Solve for y. x + 3y = 12 \n" ); document.write( "

Algebra.Com's Answer #67644 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "

Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)

Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)

$\"1x%2B3y=12\"$ Start with the given equation

$\"1x%2B3y-1x=12-1x\"$ Subtract 1x from both sides

$\"3y=-1x%2B12\"$ Simplify

$\"%283y%29%2F%283%29=%28-1x%2B12%29%2F%283%29\"$ Divide both sides by 3 to isolate y

$\"y+=+%28-1x%29%2F%283%29%2B%2812%29%2F%283%29\"$ Break up the fraction on the right hand side

$\"y+=+%28-1%2F3%29x%2B4\"$ Reduce and simplify

The original equation $\"1x%2B3y=12\"$ (standard form) is equivalent to $\"y+=+%28-1%2F3%29x%2B4\"$ (slope-intercept form)

The equation $\"y+=+%28-1%2F3%29x%2B4\"$ is in the form $\"y=mx%2Bb\"$ where $\"m=-1%2F3\"$ is the slope and $\"b=4\"$ is the y intercept.

\n" ); document.write( " \n" ); document.write( "

\n" );