document.write( "Question 92951: I will try to write this correctly -\r
\n" ); document.write( "\n" ); document.write( "5^x-1 = 125^2x+3 ( the x-1 and 2x+3 should all be in superscript and raised)
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\n" ); document.write( "lucy
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Algebra.Com's Answer #67643 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"5%5E%28x-1%29+=+125%5E%282x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%28x-1%29+=+%285%5E3%29%5E%282x%2B3%29\" Rewrite 125 as \"5%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%28x-1%29+=+5%5E%283%282x%2B3%29%29\" Multiply the exponents\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%28x-1%29+=+5%5E%286x%2B9%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "Now that we have the same base, we can set the exponents equal to each other\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=6x%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=6x%2B9%2B1\" Add 1 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x-6x=9%2B1\" Subtract 6x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-5+x=9%2B1\" Combine like terms \"1+x\" and \"-6+x\" on the left side to get \"-5+x\"\r
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\n" ); document.write( "\n" ); document.write( "\"-5+x=10\" Combine like terms 1 and 9 on the right side to get 10\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2810%29%2F%28-5%29\" Now divide both sides by -5 to isolate and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x=+-2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So our answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=+-2\"\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%28-2-1%29+=+125%5E%282%28-2%29%2B3%29\" Plug in \"x=+-2\" into the original equation\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%28-2-1%29+=+125%5E%28-4%2B3%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%28-3%29+=+125%5E%28-1%29\" Combine like terms in the exponents\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F5%5E3+=+1%2F125\" Rewrite \"125%5E%28-1%29\" as \"1%2F125%5E1\" which is just \"1%2F125\". Rewrite \"5%5E%28-3%29\" as \"1%2F5%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F125+=+1%2F125\" Evaluate \"1%2F5%5E3\" to get \"1%2F125\". Since the equations are equal, our answer is verified.
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