document.write( "Question 1061634: The length of a new rectangular playing field is 9 yards longer than double the width. If the perimeter of the rectangular playing field is 270 ​yards, what are its​ dimensions? \n" ); document.write( "
Algebra.Com's Answer #676410 by josgarithmetic(39616)\"\" \"About 
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w and L for the regular field.
\n" ); document.write( "w and 2w+9 the dimensions of the new field.\r
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\n" ); document.write( "\n" ); document.write( "2L+2w=270, the perimeter of the field (the NEW one?).
\n" ); document.write( "If this is the new field, then \"2%282w%2B9%29%2B2w=270\".
\n" ); document.write( "Ready to solve for this new width field.\r
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\n" ); document.write( "\n" ); document.write( "\"2w%2B9%2Bw=135\"
\n" ); document.write( "\"3w%2B9=135\"
\n" ); document.write( "\"3w=126\"
\n" ); document.write( "\"highlight%28w=42%29\" and \"L=2%2A42%2B9=highlight%2893%29\" length of new field.
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