document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061605>Question 1061605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> #1. 400 families were surveyed. It was found that 90% had a TV set & 60% had a computer. Every family had at least one of these items. One of these families is randomly selected & it is found that they have a computer. Find the probability that it also has a TV set.<BR>\n" );
document.write( "#2. Two dice are rolled. What is the probability of getting;<BR>\n" );
document.write( "a. Not a 3<BR>\n" );
document.write( "b. The same # on both dice<BR>\n" );
document.write( "c. A sum of 8<BR>\n" );
document.write( "d. A sum of 3 or 4<BR>\n" );
document.write( "e. A pair where the first # is less than the second #<BR>\n" );
document.write( "f. A sum of 12<BR>\n" );
document.write( "g. A sum of 20<BR>\n" );
document.write( "h. 3,4 or 6,2<BR>\n" );
document.write( "i. Two even #s<BR>\n" );
document.write( "j. A sum less than 8<BR>\n" );
document.write( "k. A sum greater than 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676387 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(TV or C)=P(TV)+p(C)-P(Both)<BR>\n" );
document.write( "1=0.9+0.6-P(Both)<BR>\n" );
document.write( "Therefore, P(Both)=0.5<BR>\n" );
document.write( "Probability choose one with a computer is 0.6<BR>\n" );
document.write( "If they have a TV, they fit into the category of having both.<BR>\n" );
document.write( "Therefore, 0.6*P(TV)=0.5<BR>\n" );
document.write( "P(TV)=0.5/0.5=0.83333 or 5/6<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "For Dice, The probability of a 3 is 2/36, 36 ways to roll and 1/2 or 2/1. So it is 33/36=11/12.<BR>\n" );
document.write( "The same number is 1/6, 11,22,33,44,55,66<BR>\n" );
document.write( "A sum of 8 is 5/36.  2/6,3/5,4/4,5/3,6/2<BR>\n" );
document.write( "A sum of 3 or 4 is 5/36:1/2,2/1,1/3,2/2,3/1<BR>\n" );
document.write( "A pair where the first number is less than the second<BR>\n" );
document.write( "1,2-1/6 (5); 2/3-2/6 (4), 3/4-3/6 (3), 4/5-4/6 (2), 5/6 (1). That is 15/36 or 5/12.<BR>\n" );
document.write( "A sum of 12 is 1/36, 6/6<BR>\n" );
document.write( "A sum of 20 is 0.<BR>\n" );
document.write( "3,4 or 6,2 is 2/36 or 1/18, assuming order matters, otherwise it is 1/9.  <BR>\n" );
document.write( "Two even numbers are 2/2,4/4,6/6 or 3/36 or 1/12<BR>\n" );
document.write( " A sum less than 8 is (1/36, 2/36,3/36,4/36,5/36,6/36)=21/36 or 7/12.<BR>\n" );
document.write( "A sum greater than 8 is 4/36,3/36,2/36,1/36=10/36=5/18<BR>\n" );
document.write( "If one makes a matrix of <BR>\n" );
document.write( "1==2==3==4==5==6<BR>\n" );
document.write( "2<BR>\n" );
document.write( "3<BR>\n" );
document.write( "4<BR>\n" );
document.write( "5<BR>\n" );
document.write( "6<BR>\n" );
document.write( "and fills it in, all these probabilities can be easily seen.  Seven is the most common sum, 1/6 times, with each number away from that sum being 1/36 less.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );