document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061614>Question 1061614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of Yolanda's closet is 2 feet longer that twice it's width. If the diagonal measures 13 feet, then what are the length and width?  <BR>\n" );
document.write( " <BR>\n" );
document.write( "there is a figure showed how one side is 2x+2 ft and 13 ft on the diagonal and x on the shortest line </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676385 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width is x<BR>\n" );
document.write( "length is 2x+2<BR>\n" );
document.write( "hypotenuse squared=x^2+(2x+2)^2=x^2+4x^2+8x+4<BR>\n" );
document.write( "That is 5x^2+8x+4=13^2=169<BR>\n" );
document.write( "or 5x^2+8x-165=0<BR>\n" );
document.write( "x=(1/10)(-8+/- sqrt (64+3300); sqrt (3364)=58<BR>\n" );
document.write( "x=(1/10)(50)=5, only positive root.<BR>\n" );
document.write( "Therefore, the width is 5 feet, length 12 feet, and diagonal is 13 feet.  This is a well known 5-12-13 right triangle.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );