document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061582>Question 1061582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 50% dye solution is to be mixed with a 75% dye solution to get 100L of a 65% solution. How much liters of the 50% Andy 75% solution will be needed  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676350 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount of 75% solution. Then the 50% solution is 100-n. So:<BR>\n" );
document.write( ".75n+.5(100-n)=.65(100)<BR>\n" );
document.write( ".25n=15<BR>\n" );
document.write( "n=60<BR>\n" );
document.write( "You need 60L of 75% solution; and 40L of 50% solution. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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