document.write( "Question 92938: In the x,y plane, what is perpendicular to the graph of the linear equation 3x-4y=0\r
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document.write( "I've done this over and over but i can't figure it out. The answer is supposed to be y=-(4/3)x+12 but i keep getting y=(3/4)x+0. Thank you for your help! \n" );
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Algebra.Com's Answer #67633 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! What is perpendicular to the graph of: \n" ); document.write( " \n" ); document.write( "You'll recall that if lines are perpendicular, then their slopes are the negative reciprocal of each other. So putting your equation into the slope-intercept form (y = mx+b) where we can readily identify the slope, m: \n" ); document.write( " \n" ); document.write( "Now that you have you slope, the slope of any line that is perpendicular to this one will be the negative reciprocal of 3/4 or -4/3, so you can write: \n" ); document.write( " \n" ); document.write( "Notice that this equation is for a whole set of lines having the same slope, not just one line, and without additional information, such as the y-intercept, you really cannot identify a specific line, can you? \n" ); document.write( "So the given answer \n" ); document.write( "The graph below should illustrate this quite clearly:(The graph of the given equation is in red) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |