document.write( "Question 92898: Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each should she use? \n" ); document.write( "
Algebra.Com's Answer #67626 by ankor@dixie-net.com(22740)\"\" \"About 
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Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each should she use?
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\n" ); document.write( "Let x = amt of pure anti-freeze required
\n" ); document.write( "Then
\n" ); document.write( "(20-x) = amt of 40% solution required:
\n" ); document.write( ":
\n" ); document.write( "The percent equation:
\n" ); document.write( ".40(20-x) + 1.0(x) = .50(20)
\n" ); document.write( "8 - .4x + x = 10
\n" ); document.write( ".6x = 10 - 8
\n" ); document.write( ".6x = 2
\n" ); document.write( "x = 2/.6
\n" ); document.write( "x = 3.33 qt of pure anti freeze
\n" ); document.write( "and
\n" ); document.write( "20 - 3.33 = 16.67 qt of 40% solution
\n" ); document.write( ":
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\n" ); document.write( "Check our solution
\n" ); document.write( ".4(16.67) + 3.33 = .5(20)
\n" ); document.write( " 6.668 + 3.33 = 9.998 ~ 10
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