document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061386>Question 1061386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A feed store sells two types of cattle feed.  One sells for $180 and the other sells for $210 per ton.  If the store wants to sell 60 tons of a mix that can be sold for $200 per ton, how much of each feed should be mixed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676224 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676224\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount of more expensive feed. Then the cheaper feed would be 60-n. So:<BR>\n" );
document.write( "210n+180(60-n)=200(60)<BR>\n" );
document.write( "30n+10800=12000<BR>\n" );
document.write( "30n=1200<BR>\n" );
document.write( "n=40<BR>\n" );
document.write( "The store needs 40 tons of $210 feed, and 20 tons of $180 feed for its' mix. &#9786;&#9786;&#9786;&#9786;<BR>\n" );
document.write( " </SPAN>\n" );
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