document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061420>Question 1061420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are four children in one family. Adam is 3 years older than Bob, who is 2 times as old as Claire. David is 1 year younger than Claire. If their combined age is 20 years, find the age of each child.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676201 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=clare=3<BR>\n" );
document.write( "x-1=david=2<BR>\n" );
document.write( "2x=bob=6<BR>\n" );
document.write( "2x+3=adam=9<BR>\n" );
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document.write( "x+x-1+2x+2x+3=20<BR>\n" );
document.write( "6x=20-2<BR>\n" );
document.write( "x=18/6<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "x-1=2<BR>\n" );
document.write( "2x=6<BR>\n" );
document.write( "2x+3=9 </SPAN>\n" );
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