document.write( "Question 1061406: the length of a rectangle is one more than twice its width. The area is 66ft squared/ how would I find the length and the width? Thank you! \n" ); document.write( "
Algebra.Com's Answer #676193 by addingup(3677)\"\" \"About 
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L = 2W+1
\n" ); document.write( "Area = 66
\n" ); document.write( "formula for area: L*W substitute for L:
\n" ); document.write( "(2W+1)*W = 66
\n" ); document.write( "from here we can solve using several methods. I'll use the factor method.
\n" ); document.write( "w*2W+W = 66
\n" ); document.write( "W^2*2+W = 66
\n" ); document.write( "W^2*2+W-66 = 0
\n" ); document.write( "2W^2+W-66 = 0 Factor the left side (FOIL):
\n" ); document.write( "(W+6)(2W-11) = 0
\n" ); document.write( "W+6 = 0 or 2W-11 = 0
\n" ); document.write( "W = -6 or W = 11/2 = 5.5
\n" ); document.write( "We are not looking for a negative number, so let's try 5.5:
\n" ); document.write( "W = 5.5 and L = 2W+1 = 2(5.5)+1 = 12
\n" ); document.write( "Area : 5.5*12 = 66 Correct.
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\n" ); document.write( "John\r
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