document.write( "Question 92881: If the sides of a square are increased by 3 in, the area is increased by 39 in. What were the dimensions of the original square? \n" ); document.write( "
Algebra.Com's Answer #67612 by psbhowmick(878)\"\" \"About 
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Let the original length of each side = x in. Then, original area = \"x%5E2\" sq in.\r
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\n" ); document.write( "\n" ); document.write( "Then, the final length of each side = (x + 3) in and final area = \"%28x+%2B+3%29%5E2\" sq in.\r
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\n" ); document.write( "\n" ); document.write( "Hence, the increment in area
\n" ); document.write( "= \"%28x%2B3%29%5E2+-+x%5E2\" sq. in
\n" ); document.write( "= \"6x%2B9\" sq. in
\n" ); document.write( "This value is equal to 39 sq. in.\r
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\n" ); document.write( "\n" ); document.write( "Hence, \"6x+%2B+9+=+39\"
\n" ); document.write( "\"6x+=+39+-+9+=+30\"
\n" ); document.write( "\"x+=+30%2F6+=+5\"\r
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\n" ); document.write( "\n" ); document.write( "Ans: Original length of the sides of the square were 5 inches.
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