document.write( "Question 5130: My question is 2 parts i solved the first part easy but the wecond part is got me stuck\r
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document.write( "The growth of a population of bacteria can be bodelled using the function P=2xe^-x where x is measured in hours and p is in millions\r
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document.write( "a) find the maximum population and when it occurs - i got 735,758 after 1 hour i think this is right \r
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document.write( "b) verify your value by finding the derivative and evaluating the maximum value - im not too sure how to do this and i cant figure out the derivative\r
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document.write( "if u could help me that would be sooo good thanks \n" );
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Algebra.Com's Answer #6761 by khwang(438) ![]() You can put this solution on YOUR website! [quote] P= 2xe^-x where x is measured in hours and p is in millions \n" ); document.write( "a) find the maximum population and when it occurs - i got 735,758 after 1 hour [/quote] \n" ); document.write( " \n" ); document.write( " dP/dx = P' = 2e^-x - 2xe^-x = 2e^-x(1-x) \n" ); document.write( " Since,e^-x > 0, we have dP/dx = 0 -->x =1.\r \n" ); document.write( "\n" ); document.write( " Note P\" = -2e^-x(1-x) -2e^-x = 2e^-x(x-3), so P\"(1) < 0. \n" ); document.write( " By the 2nd derivative test,we see that P has relative max when x = 1. \n" ); document.write( " And P(1) =0.735759377 *1 million (I really don't care about it)\r \n" ); document.write( "\n" ); document.write( " Or you use the 1st derivative test by testing P'(1+) < 0 and P'(1-) > 0. \n" ); document.write( " \n" ); document.write( " Kenny\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |