document.write( "Question 1061290: Write an equation in slope intercept form that passes trough the point (1,-6) and is parallel to the equation x-2y=4. Then write an equation that passes trough the same point but is perpendicular to the same equation. \n" ); document.write( "
Algebra.Com's Answer #676085 by math_helper(2461)\"\" \"About 
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For the given line:
\n" ); document.write( "\"+-2y+=+4+-+x+\"
\n" ); document.write( "\"+++y+=+%281%2F2%29x+-+2+\" so slope is 1/2\r
\n" ); document.write( "\n" ); document.write( "Parallel line will have slope = 1/2:
\n" ); document.write( "\"++y+=+%281%2F2%29x+%2B+b+\"\r
\n" ); document.write( "\n" ); document.write( "This line passes through (1,-6) (x=1, y=-6), use this to find 'b':
\n" ); document.write( "\"+-6+=+%281%2F2%29%281%29+%2B+b+\"
\n" ); document.write( "\"+++b+=+-%2813%2F2%29+\"
\n" ); document.write( "—
\n" ); document.write( "Equation of parallel line is:
\n" ); document.write( "\"++y+=+%281%2F2%29x+-+%2813%2F2%29+\"
\n" ); document.write( "————————\r
\n" ); document.write( "\n" ); document.write( "Perpendicular lines have slopes that are negative reciprocals: so if m is the slope of one line, then -1/m is the slope of a line perpendicular to it.\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28%28-1%29%2F%281%2F2%29%29+x+%2B+b+\"
\n" ); document.write( "\"+y+=++%28-2%29x+%2B+b+\"\r
\n" ); document.write( "\n" ); document.write( "Find b using the same technique as above (1,-6) ==> y=-6 when x=1:\r
\n" ); document.write( "\n" ); document.write( "Then solve for b then re-write the equation of the line in final form. \r
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