document.write( "Question 1061260: 2. The digits of a two-digit number differ by 2. If the digits are reversed, the new number is 18 less than the original number. Find the original number.\r
\n" ); document.write( "\n" ); document.write( "3. A total of Php500 000 is invested in 3 funds paying 6%, 8% and 10% simple interest rate.The annual income from the three investment is Php37 000. If the amount invested at 6%interest rate is twice as much of that invested in 10% interest rate, and the amount invested at 8% interest rate? \n" ); document.write( "

Algebra.Com's Answer #676079 by MathTherapy(10555) $\"\"$ $\"About$

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\n" ); document.write( "2. The digits of a two-digit number differ by 2. If the digits are reversed, the new number is 18 less than the original number. Find the original number.\r
\n" ); document.write( "\n" ); document.write( "3. A total of Php500 000 is invested in 3 funds paying 6%, 8% and 10% simple interest rate.The annual income from the three investment is Php37 000. If the amount invested at 6%interest rate is twice as much of that invested in 10% interest rate, and the amount invested at 8% interest rate?
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Let the tens, and units digits, be T and U, respectively
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document.write( "Since the reversed number is less than the original number, it follows that T will be > U
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document.write( "We then get: T - U = 2 ------- eq (i)
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document.write( "Also, 10U + T = 10T + U – 18_____10T – T + U – 10U = 18_____9T - 9U = 18____9(T - U) = 9(2)_____T - U = 2 ----- eq (ii)\r
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document.write( "Since both equations are identical, then ANY 2-digit number, with its tens digit being larger than its units digit by 2, and when reversed, results in 
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document.write( "another 2-digit number that is 18 less than the original number, WILL WORK!
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document.write( "That’s it….nothing COMPLEX, nothing to write a BOOK on!
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document.write( "BTW, 20 is not one of the original numbers, since when it's reversed, IT'S NOT a 2-digit number, so let no-one tell you otherwise!!\r
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document.write( "Try # 3. I can't do EVERYTHING for you! How would you learn if I did? \n" );
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