document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061150>Question 1061150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please solve the following problem?\r<BR>\n" );
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document.write( "The population of a town increased by 50/3% <BR>\n" );
document.write( "in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?\r<BR>\n" );
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document.write( "-Thank you.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #676066 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=676066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be your initial population. Then the town increased by 50/3% the first year, so it is 1+50/3% times its original size, or 3000 x 1.166666667, or 3500. Similarly, the next year it was 3500 x 1.1, or 3850, by the end of 1991. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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