document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92913>Question 92913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Separate 25 into two parts so that the second part is 5 less than twice the first part. Find each part. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67606 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67606\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first part = x.<BR>\n" );
document.write( "Then, second part = (25 - x).\r<BR>\n" );
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document.write( "According to the problem: <BR>\n" );
document.write( "Second part = 2(first part) - 5<BR>\n" );
document.write( "So, (25 - x) = 2x - 5<BR>\n" );
document.write( "3x = 30<BR>\n" );
document.write( "x = 30/3 = 10<BR>\n" );
document.write( "So, (25 - x) = 25 - 10 = 15\r<BR>\n" );
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document.write( "So the two parts are: 10 and 15. </SPAN>\n" );
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