document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92914>Question 92914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first side of a triangle is 40cm shorter than twice the second. The third side is 2cm longer than the second.  The perimeter is 70 cm. Find the length of each side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67605 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67605\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of second side = x cm.<BR>\n" );
document.write( "The first side is 40 cm shorter than twice the second side; hence its length = <BR>\n" );
document.write( "(2x - 40) cm.<BR>\n" );
document.write( "The third side is 2 cm longer than the second side; hence its length = (x + 2) cm.\r<BR>\n" );
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document.write( "Perimeter = sum of lengths of all sides<BR>\n" );
document.write( "70 = x + (2x - 40) + (x + 2)<BR>\n" );
document.write( "4x - 38 = 70<BR>\n" );
document.write( "4x = 70 + 38 = 108<BR>\n" );
document.write( "x = 108/4 = 27\r<BR>\n" );
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document.write( "Ans: <BR>\n" );
document.write( "1st side is (2*27 - 40 =) 14 cm, <BR>\n" );
document.write( "2nd side is 27 cm and <BR>\n" );
document.write( "3rd side is (27 + 2 =) 29 cm. </SPAN>\n" );
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