document.write( "Question 1061051: The width of a rectangle is 6cm less than twice the length. If the area is to be 20cm^2, then what is its length? Show all work. \n" ); document.write( "
Algebra.Com's Answer #676033 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the length = x \n" ); document.write( "Width = 2x - 6 \n" ); document.write( "Area = Length x Width \n" ); document.write( "20 = x(2x - 6) \n" ); document.write( "20 = 2x^2 - 6x \n" ); document.write( "Rearrange: \n" ); document.write( "2x^2 - 6x - 20 = 0 \n" ); document.write( "Divide by 2 for ease. \n" ); document.write( "2(x^2 - 3x - 10) \n" ); document.write( "Factorize \n" ); document.write( "2(x + 2)(x - 5) = 0 \n" ); document.write( "x + 2 = 0 \n" ); document.write( "x = -2 (Disregard as -ve) \n" ); document.write( "x - 5 = 0 \n" ); document.write( "x = 5 \n" ); document.write( "Length = 5 cm \n" ); document.write( "Width = 4 cm \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |