document.write( "Question 1061051: The width of a rectangle is 6cm less than twice the length. If the area is to be 20cm^2, then what is its length? Show all work. \n" ); document.write( "
Algebra.Com's Answer #676033 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Make the length = x
\n" ); document.write( "Width = 2x - 6
\n" ); document.write( "Area = Length x Width
\n" ); document.write( "20 = x(2x - 6)
\n" ); document.write( "20 = 2x^2 - 6x
\n" ); document.write( "Rearrange:
\n" ); document.write( "2x^2 - 6x - 20 = 0
\n" ); document.write( "Divide by 2 for ease.
\n" ); document.write( "2(x^2 - 3x - 10)
\n" ); document.write( "Factorize
\n" ); document.write( "2(x + 2)(x - 5) = 0
\n" ); document.write( "x + 2 = 0
\n" ); document.write( "x = -2 (Disregard as -ve)
\n" ); document.write( "x - 5 = 0
\n" ); document.write( "x = 5
\n" ); document.write( "Length = 5 cm
\n" ); document.write( "Width = 4 cm
\n" ); document.write( "Hope this helps :-)
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