document.write( "Question 1061101: The length of a rectangle is five more than twice the width. a) If the area is 18 square feet, find the dimensions of the rectangle. b) If the perimeter is 25 meters, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #676016 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Make width = x
\n" ); document.write( "Length = 5 + 2x
\n" ); document.write( "Area = Length * Width (* = times)
\n" ); document.write( "18 = (5 + 2x)x
\n" ); document.write( "18 = 5x + 2x^2
\n" ); document.write( "Rearrange
\n" ); document.write( "2x^2 + 5x - 18 = 0
\n" ); document.write( "Factorize
\n" ); document.write( "(2x + 9)(x - 2) = 0
\n" ); document.write( "2x + 9 = 0
\n" ); document.write( "2x = -9
\n" ); document.write( "x = -9/2 (Disregard as -ve)
\n" ); document.write( "x - 2 = 0
\n" ); document.write( "x = 2
\n" ); document.write( "Width = 2 ft
\n" ); document.write( "Length = 9 ft.
\n" ); document.write( "b)Using same dimensions
\n" ); document.write( "Make width = x
\n" ); document.write( "Length = 5 + 2x
\n" ); document.write( "Perimeter = 2 x Length + 2 x Width
\n" ); document.write( "25 = 2(5 + 2x) + 2(x)
\n" ); document.write( "25 = 10 + 4x + 2x
\n" ); document.write( "Rearrange
\n" ); document.write( "6x = 25 - 10
\n" ); document.write( "6x = 15
\n" ); document.write( "x = 15/6
\n" ); document.write( "x = 2.5
\n" ); document.write( "Width = 2.5 m
\n" ); document.write( "Length = 10 m
\n" ); document.write( "Hope this helps :-) \n" ); document.write( "
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