document.write( "Question 1061080: The sum of three numbers is 55. One number is five more than a second number. It is also twice the third. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #675974 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The three numbers are a, b, c \n" ); document.write( "write an equation for each statement \n" ); document.write( "Arrange the 2nd and 3rd equations so that b and c are in terms of a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of three numbers is 55. \n" ); document.write( "a + b + c = 55 \n" ); document.write( ": \n" ); document.write( " One number is five more than a second number. \n" ); document.write( "a = b + 5 \n" ); document.write( "subtract 5 from both sides \n" ); document.write( "b = a - 5 \n" ); document.write( ": \n" ); document.write( " It is also twice the third. \n" ); document.write( "a = 2c \n" ); document.write( "divide both sides by 2 \n" ); document.write( "c = .5a \n" ); document.write( ": \n" ); document.write( "Substitute for b and c in the first equation \n" ); document.write( "a + (a-5) + .5a = 55 \n" ); document.write( "2.5a - 5 = 55 \n" ); document.write( "2.5a = 55 + 5 \n" ); document.write( "2.5a = 60 \n" ); document.write( "a = 60/2.5 \n" ); document.write( "a = 24 \n" ); document.write( "find b \n" ); document.write( "b = 24 - 5 \n" ); document.write( " b = 19 \n" ); document.write( "find c \n" ); document.write( "c = .5(24) \n" ); document.write( "c = 12 \n" ); document.write( ": \n" ); document.write( "Check in the 1st equation \n" ); document.write( "24 + 19 + 12 = 55 \n" ); document.write( " |