document.write( "Question 92844: I really need help on this problem. I haven't taken algebra in years so im a little rusty.\r
\n" ); document.write( "\n" ); document.write( "Q: What is the remainder when x^3+5x^2-6x+10 is divided by x+3?\r
\n" ); document.write( "\n" ); document.write( "The book says that the answer is 46 but i'm not sure how to get that.
\n" ); document.write( "Thanks alot.
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Algebra.Com's Answer #67596 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
remember long division? ... you can use the same technique with polynomials\r
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\n" ); document.write( "\n" ); document.write( "372 is the same as 3(10^2)+7(10)+2 ... just like 3x^2+7x+2\r
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\n" ); document.write( "\n" ); document.write( "so, dividing x+3 into x^3+5x^2-6x+10 ... x goes into x^3, x^2 times ... (x^2)(x+3) is x^3+3x^2\r
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\n" ); document.write( "\n" ); document.write( "(x^3+5x^2-6x+10)-(x^3+3x^2) is 2x^2-6x+10 ... x goes into 2x^2, 2x times ... (2x)(x+3) is 2x^2+6x\r
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\n" ); document.write( "\n" ); document.write( "(2x^2-6x+10)-(2x^2+6x) is -12x+10 ... x goes into 12x+10, -12 times ... (-12)(x+3) is -12x-36\r
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\n" ); document.write( "\n" ); document.write( "(12x+10)-(-12x-36) is 46 ... this is the remainder (it is not divisible by x)\r
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\n" ); document.write( "\n" ); document.write( "this is done like long division ... with all the same power terms lined up vertically\r
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\n" ); document.write( "\n" ); document.write( "not the case here, but if you were missing a term; like x^3+x-7 (no x^2 term); you would put in a zero for a place holder x^3+0x^2+x-7 ... to keep things properly aligned
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