document.write( "Question 1061082: Hello, We are trying to follow this equation and solution. Any help to show the work would be great thanks \r
\n" ); document.write( "\n" ); document.write( "Juan is 2 years older than Sylvia. Four years ago, Sylvia was 5/6th of Juan's age. How old are both now?
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Algebra.Com's Answer #675921 by MathTherapy(10553)\"\" \"About 
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Hello, We are trying to follow this equation and solution. Any help to show the work would be great thanks \r
\n" ); document.write( "\n" ); document.write( "Juan is 2 years older than Sylvia. Four years ago, Sylvia was 5/6th of Juan's age. How old are both now?
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Let Sylvia's age be S
\n" ); document.write( "Then Juan's is: S + 2
\n" ); document.write( "Four years ago, Sylvia was S - 4
\n" ); document.write( "Four years ago, Juan was: S + 2 - 4, or S - 2
\n" ); document.write( "Since 4 years ago, Sylvia was \"%285%2F6%29%5E%28th%29\" Juan's age, THEN, we get: \"S+-+4+=+%285%2F6%29%28S+-+2%29\"
\n" ); document.write( "6S - 24 = 5(S - 2) ------- Multiplying by LCD, 6
\n" ); document.write( "6S - 24 = 5S - 10
\n" ); document.write( "6S - 5S = - 10 + 24
\n" ); document.write( "S, or Sylvia is: \"highlight_green%28matrix%281%2C2%2C+14%2C+years-old%29%29\"
\n" ); document.write( "Jaun is: 14 + 2, or \"highlight_green%28matrix%281%2C2%2C+16%2C+years-old%29%29\"
\n" ); document.write( "That's it....nothing COMPLEX! \n" ); document.write( "
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