document.write( "Question 92886: If the sides of a square are increased by 3 in, the area is increased by 39 in. What were the dimensions of the original square \n" ); document.write( "
Algebra.Com's Answer #67591 by ankor@dixie-net.com(22740)\"\" \"About 
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If the sides of a square are increased by 3 in, the area is increased by 39 in. What were the dimensions of the original square
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\n" ); document.write( "Side of original square = x
\n" ); document.write( "Area of original square = x^2
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\n" ); document.write( "Side of new square = (x+3)
\n" ); document.write( "Area of new square = (x+3)^2
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\n" ); document.write( "The problem equation:
\n" ); document.write( "New square area - original square area = 39 sq/in
\n" ); document.write( "(x+3)^2 - x^2 = 39
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\n" ); document.write( "x^2 + 6x + 9 - x^2 = 39; FOILed (x+3)(x+3)
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\n" ); document.write( "6x + 9 = 39; x^2's eliminated
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\n" ); document.write( "6x = 39 - 9
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\n" ); document.write( "x = 30/6
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\n" ); document.write( "x = 5 in, the dimension of original square
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\n" ); document.write( "Check using the area:
\n" ); document.write( "8^2 - 5^2 =
\n" ); document.write( "64 - 25 = 39
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\n" ); document.write( "Did this make sense to you? Not that hard, right? \n" ); document.write( "
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