document.write( "Question 1061082: Hello, We are trying to follow this equation and solution. Any help to show the work would be great thanks \r
\n" ); document.write( "\n" ); document.write( "Juan is 2 years older than Sylvia. Four years ago, Sylvia was 5/6th of Juan's age. How old are both now?
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Algebra.Com's Answer #675904 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
J = S+2 or we can state it as S = J-2. Next we'll use J-2 for S.
\n" ); document.write( "S-4 = 5/6(J-4) remember, 4 year ago they were BOTH 4 yrs younger
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\n" ); document.write( "Substitute for S and distribute 5/6 on right (distributive property of multiplication 2(2+3) is the same as 4+6)
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\n" ); document.write( "J-2-4 = 5/6J-20/6 add/subtract on left and simplify the fraction, divide up/down by 2:
\n" ); document.write( "J-6 = 5/6J-10/3 now it's just algebra from here on:
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\n" ); document.write( "J-6+10/3 = 5/6J add on left. Any number can be turned into a fraction, every number is divisible by itself and by 1: -6/1+10/3 multiply -6/1 times 3/3 to get a common denominator: -18/3+10/3 = -8/3`
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\n" ); document.write( "Now we have:`
\n" ); document.write( "J-8/3 = 5/6J
\n" ); document.write( "J = 5/6J+8/3
\n" ); document.write( "J-5/6J = 8/3
\n" ); document.write( "OK, now subtract 5/6 J from J. J is just 1 J and like we said, we can turn it into a fraction like this: 1/1
\n" ); document.write( "So: 1/1-5/6 = 6/6-5/6 = 1/6
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\n" ); document.write( "And now we have:`
\n" ); document.write( "1/6J = 8/3 divide both sides by 1/6
\n" ); document.write( "J = 8/3*6/1 = 48/3 = 16/1 or just 16
\n" ); document.write( "Juan is 16. And Sylvia is 16-2 = 14
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\n" ); document.write( "Check, 4 years ago
\n" ); document.write( "J = 16-4 = 12
\n" ); document.write( "S = 14-4 = 10
\n" ); document.write( "Sylvia was 5/6 of J's age (5/6 of 12)
\n" ); document.write( "12*5/6 = 60/6 = 10 Sylvia was 10 - Correct
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\n" ); document.write( "Lots of typing, here's hoping it helps.
\n" ); document.write( "John\r
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