document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061065>Question 1061065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given ad and bc bisect each other at e prove Abe = dce </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675895 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5348)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If AD and BC bisect each other at E, E is the midpoint of AD,<BR>\n" );
document.write( "and E is also the midpoint of BC.<BR>\n" );
document.write( "AE is congruent with DE because E is the midpoint of AD.<BR>\n" );
document.write( "EB is congruent with EC because E is the midpoint of BC.<BR>\n" );
document.write( "Angles AEB and DEC are congruent with each other,<BR>\n" );
document.write( "because they are vertical angles,<BR>\n" );
document.write( "formed by the intersection of lines AD and BC at point E.<BR>\n" );
document.write( "That makes triangles AEB and DEC congruent by SAS (side-angle-side),<BR>\n" );
document.write( "since they have congruent angles at E,<BR>\n" );
document.write( "Flanked by pairs of congruent sides.<BR>\n" );
document.write( "By CPCTC (Corresponding Parts of Congruent Triangles are Congruent),<BR>\n" );
document.write( "Their corresponding angles at B and C (DCE and ABE) are congruent.<BR>\n" );
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