document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92882>Question 92882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to complete the conjecture based on the pattern that I see in this specific cases.<BR>\n" );
document.write( "Conjecture: For any number two numbers a and b, the product of (a+b) and (a-b) is always equal to _?_ <BR>\n" );
document.write( "(2+1)*(2-1)=3=2^2-1^2   (4+2)*(4-2)=12=4^2-2^2 <BR>\n" );
document.write( "(3+2)*(3-2)=5=3^2-2^2   (6+3)*(6-3)=27=6^2-3^2 \r<BR>\n" );
document.write( "\n" );
document.write( "I have no clue on how to do this one!! <BR>\n" );
document.write( "Please help!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67584 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For any number two numbers a and b, the product of (a+b) and (a-b) is always equal to _?_ <BR>\n" );
document.write( "(2+1)*(2-1)=3=2^2-1^2 <BR>\n" );
document.write( "(4+2)*(4-2)=12=4^2-2^2 <BR>\n" );
document.write( "(3+2)*(3-2)=5=3^2-2^2 <BR>\n" );
document.write( "(6+3)*(6-3)=27=6^2-3^2 <BR>\n" );
document.write( "(a+b)*(a-b) = a^2-b^2<BR>\n" );
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document.write( "You could check this using FOIL.<BR>\n" );
document.write( "========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );