document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92858>Question 92858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are decreased by 2 cm, the area is decreased by 36cm^2. What were the dimensions of the original square?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67581 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X^2=AREA OF ORIGINAL SQUARE<BR>\n" );
document.write( "X^2-36=(X-2)(X-2)<BR>\n" );
document.write( "X^2-36=(X-2)(X-2)<BR>\n" );
document.write( "X^2-36=X^2-4X=4<BR>\n" );
document.write( "X^2-X^2+4X=4+36<BR>\n" );
document.write( "4X=40<BR>\n" );
document.write( "X=40/4<BR>\n" );
document.write( "X=10 ANSWER FOR THE ORIGINAL SIDE LENGTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "10*10-36=(8*8)<BR>\n" );
document.write( "100-36=64<BR>\n" );
document.write( "64=64<BR>\n" );
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