document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060988>Question 1060988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem by making up an equation. A child is 12 years old, and his father is 32 years older. In how many years will the age of the father be 3 times the age of the child? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675806 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the number of years until a 44-year old father (12+32) is 3 times older than his 12-year old child. Then:<BR>\n" );
document.write( "44+n=3(12+n)<BR>\n" );
document.write( "44+n=36+3n<BR>\n" );
document.write( "2n=8<BR>\n" );
document.write( "n=4<BR>\n" );
document.write( "In 4 years, the father will be 48; and the child 16-making the father 3 times older than the child. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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