document.write( "Question 92873This question is from textbook Algebra and Trigonometry
\n" ); document.write( ": The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period? \n" ); document.write( "
Algebra.Com's Answer #67580 by stanbon(75887)\"\" \"About 
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The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should it be shortened to achieve a 1 second period?
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\n" ); document.write( "Period = k(length)^2
\n" ); document.write( "If P = 2 sec and length = 6, find \"k\".
\n" ); document.write( "2 = k (6)^2
\n" ); document.write( "k = 2/36
\n" ); document.write( "k = 1/18
\n" ); document.write( "EQUATION for this pendulum:
\n" ); document.write( "Period = (1/18)(length)^2
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\n" ); document.write( "If the period is 1 second find the length:
\n" ); document.write( "1 = (1/18)(length)^2
\n" ); document.write( "length^2 = 18
\n" ); document.write( "length = 3sqrt(2) ft.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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