document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92870>Question 92870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man drove 220 miles in 3 1/2 hours. Part of the trip was at 60 miles per hour and the rest at 65 miles per hour. find the time spent at lower speed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67579 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 220=60T+65(3.5-T)<BR>\n" );
document.write( "220=60T+227.5-65T<BR>\n" );
document.write( "220-227.5=-5T<BR>\n" );
document.write( "-5T=-7.5<BR>\n" );
document.write( "T=-7.5/-5<BR>\n" );
document.write( "T=1.5 HOURS AT THE SLOWER RATE OF 60MPH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "220=60*1.5+65*2<BR>\n" );
document.write( "220=90+130<BR>\n" );
document.write( "220=220<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );