document.write( "Question 92851This question is from textbook
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document.write( ": 1) Find the domain and explain the answers for each
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document.write( "a) f(t)= 4.5e^t
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document.write( "b) g(x) = log(x+3) \r
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document.write( "Is the base g? which makes it g = log x+3? throwing up hands pulling out hair\r
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document.write( "c) g(x) = 2^x
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document.write( "d) g(t)=ln(t-1)
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document.write( "This is driving me nuts. can someone explain this to me in a simple way? \n" );
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Algebra.Com's Answer #67578 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1) Find the domain and explain the answers for each \r \n" ); document.write( "\n" ); document.write( "a) f(t)= 4.5e^t \n" ); document.write( "t can take on any value so the domain is \"all Real Numbers\". \n" ); document.write( "------------ \n" ); document.write( "b) g(x) = log(x+3) \n" ); document.write( "Is the base g? \n" ); document.write( "The base is 10 when the word \"log\" is used, unless a different base is specified. \n" ); document.write( "Since you can only find logs of non-negative numbers x+3 must be greater \n" ); document.write( "than or equal to 0. Therefore x must be greater than or equal to -3. \n" ); document.write( "Therefore the domain is \"all Real numbers greater than or equal to -3\". \n" ); document.write( "--------------------- \n" ); document.write( "c) g(x) = 2^x \n" ); document.write( "x can take on any value so the domain is \"all Real Numbers\". \n" ); document.write( "----------------------- \n" ); document.write( "d) g(t)=ln(t-1) \n" ); document.write( "The t-1 must be greater than or equal to zero. \n" ); document.write( "So t must be greater than or equal to 1. \n" ); document.write( "So the domain is \"all Real Numbers greater than or equal to 1\". \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |