document.write( "Question 1060938: A car and a bus set out at 2 pm from the same point, headed in the same direction. The average speed of the car is 30 mph less than twice the average speed of the bus. In 2 hrs, the car is 30 miles ahead of the bus. Find the rate of the car. \n" ); document.write( "

Algebra.Com's Answer #675772 by ikleyn(52798) $\"\"$ $\"About$

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\n" ); document.write( "A car and a bus set out at 2 pm from the same point, headed in the same direction.
\n" ); document.write( "The average speed of the car is 30 mph less than twice the average speed of the bus.
\n" ); document.write( "In 2 hrs, the car is 30 miles ahead of the bus. Find the rate of the car.
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document.write( "The first equation is\r\n" );
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document.write( "C = 2B - 30,     (1)   where C is the car speed, B is the bus speed.\r\n" );
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document.write( "The second equation is \r\n" );
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document.write( "2C - 2B = 30.    (2)\r\n" );
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document.write( "Rewrite the equations in this form\r\n" );
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document.write( " C - 2B = -30,    (1')\r\n" );
document.write( "2C - 2B =  30.    (2')\r\n" );
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document.write( "Distract the equation (1') from equation (2') (both sides). You will get\r\n" );
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document.write( "2C - C = 30 - (-30),\r\n" );
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document.write( "C = 60.\r\n" );
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document.write( "So, you just found the speed of the car it is 60 mph.\r\n" );
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document.write( "From this point please complete the solution on your own.\r\n" );
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