document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060933>Question 1060933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimiter of a rectangle is 210 feet. the length is 10 feet longer than the width w. which equation can be used to calculate the length and the width of the playground </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675763 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w = width<BR>\n" );
document.write( "w + 10 = length   {length is 10 ft longer than the width}\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2w + 2(w + 10) = 210   {substituted width and length into perimeter formula}<BR>\n" );
document.write( "2w + 2w + 20 = 210   {used distributive property}<BR>\n" );
document.write( "4w + 20 = 210   {combined like terms}<BR>\n" );
document.write( "<br>For more help from me, visit: <a  rel=nofollow HREF= \"http://www.algebrahouse.com/\" target = \"_blank\">www.algebrahouse.com</a><br><br><br> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );