document.write( "Question 1060876: If logx-log(2x-1)is equal to 1,find x \n" ); document.write( "
Algebra.Com's Answer #675729 by ankor@dixie-net.com(22740)\"\" \"About 
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If logx-log(2x-1)is equal to 1,find x
\n" ); document.write( "Combine into a single log
\n" ); document.write( "\"log%28%28x%2F%282x-1%29%29%29+=+1\"
\n" ); document.write( "find the antilog of both sides
\n" ); document.write( "\"%28x%2F%282x-1%29%29+=+10\"
\n" ); document.write( "multiply both sides (2x-1)
\n" ); document.write( "x = 10(2x-1)
\n" ); document.write( "x = 20x - 10
\n" ); document.write( "10 = 20x - x
\n" ); document.write( "10 = 19x
\n" ); document.write( "x = \"10%2F19\"
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check on you your calc enter
\n" ); document.write( "log(10/19) - log(2(10/19)-1)) =\r
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