document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060604>Question 1060604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this equation : DETERMINE the equation of the line with the vertical intercept of (0,12) and parallel to the line of y=-3x+7. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675716 by </B><A HREF=/tutors/aboutme.mpl?userid=0764229590><B>0764229590(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=0764229590><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=0764229590><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since the lines are parallel,<BR>\n" );
document.write( "therefore the gradient of the other line is also -3\r<BR>\n" );
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document.write( ".'.y=-3x+c<BR>\n" );
document.write( "substitute the point (0;12) to solve c<BR>\n" );
document.write( ".'.12=-3(0)+c<BR>\n" );
document.write( "   12=0+c<BR>\n" );
document.write( "then c=12\r<BR>\n" );
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document.write( "therefore y=-3x+12 </SPAN>\n" );
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