document.write( "Question 1060753: A pharmacist has a 12% solution of boric acid and a 20% solution of boric acid. How much of each must he use to make 80 grams of a 15% boric acid solution \n" ); document.write( "
Algebra.Com's Answer #675628 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A pharmacist has a 12% solution of boric acid and a 20% solution of boric acid. \n" ); document.write( " How much of each must he use to make 80 grams of a 15% boric acid solution. \n" ); document.write( ": \n" ); document.write( "let x = amt of 20% solution required \n" ); document.write( "the resulting amt is to be 80 grams therefore \n" ); document.write( "(80-x) = amt of 12% solution needed \n" ); document.write( ": \n" ); document.write( "A decimal equiv of per cent equation \n" ); document.write( ".20x = .12(80-x) = .15(80) \n" ); document.write( ".20x + 9.6 - .12x = 12 \n" ); document.write( ".20x - .12x = 12 - 9.6 \n" ); document.write( ".08x = 2.4 \n" ); document.write( "x = 2.4/.08 \n" ); document.write( "x = 30 grams of the 20% solution \n" ); document.write( "and obviously \n" ); document.write( "80 - 30 = 50 grams of the 12% \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check \n" ); document.write( ".20(30) + .12(50) = .15(80) \n" ); document.write( "6 + 6 = 12 \n" ); document.write( " \n" ); document.write( " |