document.write( "Question 1060705: long division: (x^3-3x^2+2x-8)/(x^2+4)\r
\n" ); document.write( "\n" ); document.write( "and find the 9th term of:
\n" ); document.write( "(x^2-2)^9\r
\n" ); document.write( "\n" ); document.write( "I need help i'm completely confused on long division and terms. I don't understand the formulas. Can you help?
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Algebra.Com's Answer #675621 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
long division: (x^3-3x^2+2x-8)/(x^2+4)\r
\n" ); document.write( "\n" ); document.write( "and find the 9th term of:
\n" ); document.write( "(x^2-2)^9\r
\n" ); document.write( "\n" ); document.write( "I need help i'm completely confused on long division and terms. I don't understand the formulas. Can you help?
\n" ); document.write( "

\n" ); document.write( "The formula you need for the 9th term of a BINOMIAL EXPANSION is: , where, in this case:
\n" ); document.write( "a = \"x%5E2\"
\n" ); document.write( "b = - 2
\n" ); document.write( "n = 9
\n" ); document.write( "r, or term number = 9\r
\n" ); document.write( "\n" ); document.write( "Therefore, becomes:
\n" ); document.write( "
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\n" ); document.write( "It is that easy....nothing too COMPLEX! \n" ); document.write( "
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