document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060743>Question 1060743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has an area of 180 cm^2. When the length and the width are shortened by 1 cm each, the area is reduced by 27 cm^2. Find the new perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675617 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sides are x and y<BR>\n" );
document.write( "xy=180<BR>\n" );
document.write( "(x-1)(y-1)=153.<BR>\n" );
document.write( "xy-y-x+1=153<BR>\n" );
document.write( "180-y-x+1=153<BR>\n" );
document.write( "-x-y+1=-27<BR>\n" );
document.write( "x+y-1=27<BR>\n" );
document.write( "x+y=28<BR>\n" );
document.write( "but x=180/y<BR>\n" );
document.write( "so 180/y +y=28<BR>\n" );
document.write( "multiply by y<BR>\n" );
document.write( "180+y^2=28y<BR>\n" );
document.write( "y^2-28y+180=0<BR>\n" );
document.write( "(x-18)(x-10)=0<BR>\n" );
document.write( "x=18, 10<BR>\n" );
document.write( "if x=18, y=10<BR>\n" );
document.write( "shorten each by 1 cm and 17+9=153 or 27 cm^2 less.<BR>\n" );
document.write( "But the perimeter is desired, and that would be 26*2=52 cm., twice 17 plus twice 9.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );