document.write( "Question 1060645: Could you please help me. How can I solve this system of equation using the substitution method.
\n" ); document.write( "-5x+y=-3
\n" ); document.write( "3x-8y=24
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Algebra.Com's Answer #675527 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's solve for y in equation 1\r
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\n" ); document.write( "\n" ); document.write( "-5x+y=-3\r
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\n" ); document.write( "\n" ); document.write( "-5x+y-5x=-3-5x\r
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\n" ); document.write( "\n" ); document.write( "y=-3-5x\r
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\n" ); document.write( "\n" ); document.write( "Now we'll use y=-3-5x to plug into the other equation\r
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\n" ); document.write( "\n" ); document.write( "3x-8y = 24\r
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\n" ); document.write( "\n" ); document.write( "3x-8( y ) = 24\r
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\n" ); document.write( "\n" ); document.write( "3x-8( -3-5x ) = 24 ... replace y with -3-5x; solve for x\r
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\n" ); document.write( "\n" ); document.write( "3x-8(-3)+8(-5x) = 24\r
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\n" ); document.write( "\n" ); document.write( "3x+24-40x = 24\r
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\n" ); document.write( "\n" ); document.write( "3x-40x+24 = 24\r
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\n" ); document.write( "\n" ); document.write( "-37x+24 = 24\r
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\n" ); document.write( "\n" ); document.write( "-37x+24-24 = 24-24\r
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\n" ); document.write( "\n" ); document.write( "-37x = 0\r
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\n" ); document.write( "\n" ); document.write( "-37x/(-37) = 0/(-37)\r
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\n" ); document.write( "\n" ); document.write( "x = 0\r
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\n" ); document.write( "\n" ); document.write( "Now that we know x = 0, we can use this to find y\r
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\n" ); document.write( "\n" ); document.write( "y=-3-5x\r
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\n" ); document.write( "\n" ); document.write( "y=-3-5*0 ... replace x with 0\r
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\n" ); document.write( "\n" ); document.write( "y=-3-0\r
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\n" ); document.write( "\n" ); document.write( "y=-3\r
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\n" ); document.write( "\n" ); document.write( "So together, x = 0 and y = -3. \r
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\n" ); document.write( "\n" ); document.write( "They form the ordered pair (0,-3)\r
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\n" ); document.write( "\n" ); document.write( "Visually, the two equations will graph 2 straight lines that meet at (0,-3)
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