document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060618>Question 1060618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object is thrown upward with a velocity of 48.0 m/s. When will it be 25.0 m above its initial position?\r<BR>\n" );
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document.write( "Note that g = 9.8 m/s2. Round to three decimal places. Give answers in increasing order.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675508 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> height=-9.8t^2+48t<BR>\n" );
document.write( "25=-9.8t^2+48t<BR>\n" );
document.write( "9.8t^2-48t+25=0, moving and checking signs.<BR>\n" );
document.write( "t=(1/19.6)(48+/-sqrt(2304-980); sqrt (1324)=36.387<BR>\n" );
document.write( "t=(11.613/19.6)=0.593 sec<BR>\n" );
document.write( "t=84.387/19.6=4.305 sec<BR>\n" );
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