document.write( "Question 1060581: Jack & Jill charge $20 for a custom painted water pail. They currently sell 80 water pails a month. They estimate that for each $1 decrease in the cost of the pails, they could sell 15 more pails a month. What price will maximize Jack & Jill's income? If they charges this price, how much income should they expect? \n" ); document.write( "
Algebra.Com's Answer #675504 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
r, income
\n" ); document.write( "x, how many pails sold
\n" ); document.write( "p, price per pail
\n" ); document.write( "\"r=px\"\r
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\n" ); document.write( "\n" ); document.write( "n, each dollar decrease in price
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\r\n" );
document.write( "PRICE    x\r\n" );
document.write( " 20      80\r\n" );
document.write( " 20-1    80+15\r\n" );
document.write( " 20-2    80+2*15\r\n" );
document.write( " 20-3    80+3*15\r\n" );
document.write( " 20-n    80+n*15 or 80+15n\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28r=%2820-n%29%2880%2B15n%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "r is a parabolic function with zeros at \"%2820-n%29%2880%2B15n%29=0\", and the MAXIMUM revenue will be exactly in the middle of the two zeros for n.\r
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\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "\"20-n=0\"
\n" ); document.write( "\"n=20\"
\n" ); document.write( "-
\n" ); document.write( "\"80%2B15n=0\"
\n" ); document.write( "\"15n=-80\"
\n" ); document.write( "\"n=-80%2F15\"
\n" ); document.write( "\"n=-5%261%2F3\"
\n" ); document.write( "-
\n" ); document.write( "MIDDLE n VALUE
\n" ); document.write( "\"%2820-5%261%2F3%29%2F2\"
\n" ); document.write( "\"highlight%28n=7%261%2F3%29\"----------how many dollars LESS THAN 20, for maximum revenue.\r
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\n" ); document.write( "\n" ); document.write( "If Jack and Jill want a price to the nearest penny, then this would be $7.33 per pail.
\n" ); document.write( "Revenue would be \"r=7.33%2880%2B7.33%2A15%29=highlight%281392.33%29\".
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