document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92819>Question 92819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sally bought three chocolate bars and a pack of gum and paid $1.75. Jake bought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67547 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3C+G=1.75 OR G=1.75-3C<BR>\n" );
document.write( "2C+4G=2.00 NOW SUBSTITUTE (1.75-3C) FOR G IN THIS EQUATION & SOLVE FOR C.<BR>\n" );
document.write( "2C+4(1.75-3C)=2.00<BR>\n" );
document.write( "2C+6.00-12C=2.00<BR>\n" );
document.write( "-10C=2.00-6.00<BR>\n" );
document.write( "-10C=-4.00<BR>\n" );
document.write( "C=-4.00/-10<BR>\n" );
document.write( "C=.40 COST OF THE GUM.<BR>\n" );
document.write( "3C+.40=1.75<BR>\n" );
document.write( "3C=1.75-40<BR>\n" );
document.write( "3C-1.35<BR>\n" );
document.write( "C=1.35/3<BR>\n" );
document.write( "C=.45 COST OF THE CHOCOLATE. </SPAN>\n" );
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