document.write( "Question 1060529: Ravi bought a desktop computer and a laptop computer. Before finance charges, the laptop cost
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document.write( "$300
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document.write( " less than the desktop. He paid for the computers using two different financing plans. For the desktop the interest rate was
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document.write( "6%
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document.write( " per year, and for the laptop it was
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document.write( "7%
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document.write( " per year. The total finance charges for one year were
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document.write( "$252
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document.write( ". How much did each computer cost before finance charges? \n" );
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Algebra.Com's Answer #675461 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let d = cost of desktop \n" ); document.write( "and let a = cost of laptop \n" ); document.write( "-- \n" ); document.write( "Write down what we know \n" ); document.write( " a = d - 300 (1) \n" ); document.write( "0.06d + 0.07a = 252 (2) \n" ); document.write( "— \n" ); document.write( "Eq (1) allows us to substitute \"d-300\" for \"a\" in (2): \n" ); document.write( " 0.06d + 0.07(d-300) = 252 \n" ); document.write( " 0.13d - 21 = 252 \n" ); document.write( " 0.13d = 273 \n" ); document.write( " d = 273/0.13 = 2100\r \n" ); document.write( "\n" ); document.write( "— \n" ); document.write( "Ans: \n" ); document.write( "Desktop cost was $2100 \n" ); document.write( "Laptop cost was therefore $1800 \n" ); document.write( "—\r \n" ); document.write( "\n" ); document.write( "Check: 2100(0.06) + 1800(0.07) = 126 + 126 = 252 (ok, finance charges add up) \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |