document.write( "Question 1060529: Ravi bought a desktop computer and a laptop computer. Before finance charges, the laptop cost
\n" ); document.write( "$300
\n" ); document.write( " less than the desktop. He paid for the computers using two different financing plans. For the desktop the interest rate was
\n" ); document.write( "6%
\n" ); document.write( " per year, and for the laptop it was
\n" ); document.write( "7%
\n" ); document.write( " per year. The total finance charges for one year were
\n" ); document.write( "$252
\n" ); document.write( ". How much did each computer cost before finance charges?
\n" ); document.write( "

Algebra.Com's Answer #675461 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Let d = cost of desktop
\n" ); document.write( "and let a = cost of laptop
\n" ); document.write( "--
\n" ); document.write( "Write down what we know
\n" ); document.write( " a = d - 300 (1)
\n" ); document.write( "0.06d + 0.07a = 252 (2)
\n" ); document.write( "—
\n" ); document.write( "Eq (1) allows us to substitute \"d-300\" for \"a\" in (2):
\n" ); document.write( " 0.06d + 0.07(d-300) = 252
\n" ); document.write( " 0.13d - 21 = 252
\n" ); document.write( " 0.13d = 273
\n" ); document.write( " d = 273/0.13 = 2100\r
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( "Ans:
\n" ); document.write( "Desktop cost was $2100
\n" ); document.write( "Laptop cost was therefore $1800
\n" ); document.write( "—\r
\n" ); document.write( "\n" ); document.write( "Check: 2100(0.06) + 1800(0.07) = 126 + 126 = 252 (ok, finance charges add up)
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );