document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060466>Question 1060466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> &#8710;BAC is right angled at A. The bisectors of angle B and C meet at O . Find angle BOC. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675409 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52877)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "= 360° -90° - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%5Eo%2F2 ALIGN=MIDDLE  ALT=\"90%5Eo%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 225°.\r<BR>\n" );
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document.write( "360° is the sum of interior angles of the quadrilateral ABOC.\r<BR>\n" );
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document.write( "90° is the right angle A.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%5Eo%2F2 ALIGN=MIDDLE  ALT=\"90%5Eo%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the sum of the measures of angles ABO and ACO.\r<BR>\n" );
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