document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060426>Question 1060426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The negative difference between the measures of supplementary angles is -45. Find the measures of the larger angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675358 by </B><A HREF=/tutors/aboutme.mpl?userid=annemsujan><B>annemsujan(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=annemsujan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=annemsujan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given,\r<BR>\n" );
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document.write( "eq1: x+y = 180 (supplementary angles)<BR>\n" );
document.write( "eq2: x-y= -45\r<BR>\n" );
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document.write( "Solving eq1 - eq2, you can evaluate value of y (larger angle)\r<BR>\n" );
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document.write( "x+y - (x-y) = 180 - (-45)\r<BR>\n" );
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document.write( "2y = 225\r<BR>\n" );
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document.write( "y = 112.5 </SPAN>\n" );
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