document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060337>Question 1060337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves Philadelphia at 5:00 PM. A second train leaves the same city in the same direction at 7:00 PM. The second train travels 30 mph faster than the first. If the second train overtakes the first at 11:00 PM, what is the speed of each of the two trains? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675339 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the speed of the slower train.  Then the faster train is n+30. Since the slow train has a headstart of two hours that is 2n. So<BR>\n" );
document.write( "2n+4n=4(n+30)<BR>\n" );
document.write( "6n=4n+120<BR>\n" );
document.write( "2n=120<BR>\n" );
document.write( "n=60<BR>\n" );
document.write( "The slow train has a speed of 60 mph; the faster train goes 90 mph. </SPAN>\n" );
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