document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060303>Question 1060303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bobet is 3 more than 4 times the age of his son. Next year The sum of their ages will be 40. How old is Bobet? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675333 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the age of Bobet's son. Then Bobet is 4n+3. The next year, their ages will be n+1 and 4n+4. So:<BR>\n" );
document.write( "n+1+4n+4=40<BR>\n" );
document.write( "5n=35<BR>\n" );
document.write( "n=7<BR>\n" );
document.write( "Bobet's son is now 7; Bobet is 31. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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