document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92801>Question 92801</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain of the following function:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%283x-2%29%2F%284x%2B1%29 ALIGN=MIDDLE  ALT=\"y=%283x-2%29%2F%284x%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Would I go about this by solving for x?  I'm not really sure how to start this.  If you could just show me the steps to finding the solution for this problem, I would greatly appreciate it!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67533 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%283x-2%29%2F%284x%2B1%29 ALIGN=MIDDLE  ALT=\"y=%283x-2%29%2F%284x%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "The domain is the spectrum of values that x can take. In this problem there is only one<BR>\n" );
document.write( "consideration that limits the value of x. Notice that there is a denominator that contains x.<BR>\n" );
document.write( "Also recall that algebraic rules do not permit division by zero. Therefore, the denominator<BR>\n" );
document.write( "cannot equal zero.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "So we can write the equation:<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x+%2B+1+=+0 ALIGN=MIDDLE  ALT=\"4x+%2B+1+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "Subtract 1 from both sides and we get:<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x+=+-1 ALIGN=MIDDLE  ALT=\"4x+=+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "Finally, divide both sides by 4 to find x and you get:<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-1%29%2F4 ALIGN=MIDDLE  ALT=\"x+=+%28-1%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "This tells us that if <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-1%29%2F4 ALIGN=MIDDLE  ALT=\"x+=+%28-1%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > then the denominator equals zero. Therefore,<BR>\n" );
document.write( "x cannot be equal to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%29%2F4 ALIGN=MIDDLE  ALT=\"%28-1%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Other than that single exception, x can have any value <BR>\n" );
document.write( "from minus infinity to plus infinity.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Hope this helps you to understand the problem a little more.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );