document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060329>Question 1060329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jim's yard is in the shape of a rectangle. The length is five feet longer than twice the width. The perimeter of the yard is 400 feet. Determine the length and width of this yard. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #675323 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=675323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2l+2w<BR>\n" );
document.write( "400=2l+2w<BR>\n" );
document.write( "200=l+w<BR>\n" );
document.write( "but l=2w+5<BR>\n" );
document.write( "Therefore, 2w+5+w=200<BR>\n" );
document.write( "3w=195<BR>\n" );
document.write( "w=65 feet ANSWER<BR>\n" );
document.write( "length=135 feet ANSWER<BR>\n" );
document.write( "2l=270<BR>\n" );
document.write( "2w=130<BR>\n" );
document.write( "Total = 400 feet. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );